Question

A current of 0.5A is drawb b6 a filament of an electric bulb​

Answer 1

Answer:

• The amount of electric charge that flows through the circuit is 300c.

Explanation:

Given that,

• Current (I) = 0.5 A
• Time (t) = 10min

We know,

$\pink\bigstar$ 1min = 60sec

↪ Time (t) = 10 × 60 = 600sec

As we know that,

$\sf \: \red \bigstar \: \: \orange{Current( I)= \frac{Electric \: charge(Q) }{Time(t)}}$

[ Putting values ]

$\longrightarrow \sf \: 0.5 = \frac{Q}{600} \\ \\ \longrightarrow \sf \: Q =0.5 \times 600 \\ \\ \longrightarrow \sf \underbrace{Q = 300c} \: \: \green \bigstar$

Answer 2

Question :

A current of 0.5A is drawn by a filament of an electric bulb for 10 minutes. Find the amount of electric charge that flows through the circuit.

Given :

• Current flowing (I) =  0.5 Ampere
• Time given (t) = 10 minutes

                                = (10 * 60) s

                                = 600 s

To find :

• Amount of electric charge.

Solution :

Amount of electric charge is given by,

$\longmapsto\boxed{\boxed{\sf{Current \ flowing\ (I) = \dfrac{Electric \ charge\ (Q)}{Time \ (t) } }}}$

Putting values :

$\longmapsto\sf 0.5 = \dfrac{Electric \ charge}{600} \\\\\ \\ \longmapsto\sf Electric \ charge = 0.5 \times 600 \\\\ \\ \longmapsto\sf Electric \ charge = \dfrac{1}{2} \times 600 \\\\ \\ \longmapsto\boxed{\underline{\overline{\bf{\mid{Electric \ charge = 300 \ C \mid}}}}}$

$\therefore\underline{\textsf{Amount of electric charge flowing = {\textbf{300 C}}}}$