A current of 0.5a is drawn by a filament of an electric bulb for 10min find the number of electrons which contribute to this charge
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given
I=0.5A
T=10 min
=10*60 s=600 s
charge=current*time
=0.5*600
=5*60
=300 Coulomb
1 C=6.25*10^18 electrons
300 C=300*6.25*10^18 electrons
=3*625*10^18
=1875*10^18
=1.875*10^21 electrons
I=0.5A
T=10 min
=10*60 s=600 s
charge=current*time
=0.5*600
=5*60
=300 Coulomb
1 C=6.25*10^18 electrons
300 C=300*6.25*10^18 electrons
=3*625*10^18
=1875*10^18
=1.875*10^21 electrons
Anonymous:
is it right??
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