Question

a current of 0.5A passes for 10 minutes.
Find (a) The amount of charge
passed.

(b) Number of electrons
passed in 1 minute.​

Answer 1

Question :-

A current of 0.5 A passes for 10 minutes.

To find :-

(i) The amount of charge passed

(ii) Number of electrons passed in 1 minute.

Solution :-

(i)

we are given,

• I = 0.5A
• T = 10 minutes
• 10 minutes = 600 sec

we know that,

I = Q/T

or, Q = IT

• where, Q is charge
• I is current
• T is time

Q = 0.5 x 600

Q = 300C

__________________________

(ii)

Here,

• t = 1 min
• 1 min = 60sec
• I = 0.5 A

so,

Q = It

Q = 0.5 x 60

Q = 30C

Number of electrons = total charge/charge in 1 electron

= 30/1.6 x 10^-19

= 1.8 x 10^-19

Answer 2

$\huge \fcolorbox{red}{pink}{Solution :)}$

i) Given ,

Current = 0.5 amp

Time = 10 min or 600 sec

We know that , the rate of unit charge is called current

$\mathtt{ \fbox{Current = \frac{charge \: (q)}{time \: (t)} }}$

Substitute the known values , we get

Charge (q) = 0.5 × 600

Charge (q) = 5 × 60

Charge (q) = 300 coulomb

Hence , 300 coulomb charge is passed

ii) Given ,

Current = 0.5 amp

Time = 1 min or 60 sec

Therefore ,

Charge (q) = 0.5 × 60

Charge (q) = 30 coulomb

Also , we know that , total charge of a body is always an integral multiples of electrons

$\large \mathtt{ \fbox{ Charge \: (q) = ne}}$

Where ,

e is electron which is equal to 1.6 × (10)^-19

Substitute the known values , we get

$\sf \hookrightarrow 30 = n \times 1.6 \times {(10)}^{ - 19} \\ \\\sf \hookrightarrow n = \frac{30}{1.6 \times {(10)}^{ - 19} } \\ \\\sf \hookrightarrow n = 0.18 \times {(10)}^{21}$

Hence , the number of electrons is 0.18 × (10)^21

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