Question

a current of 0.5ampere passes through a conductor 4 sec.. findthe net charge flowing and the number of electrons flowing​

Answer 1

Explanation:

Given:

I = 0.5 A ; t = 2 s

Solution:

Q (charge) = I / t

Q = 0.5 / 2 = 0.25

Total charge

_____________________

No. of electron = [ n (e) = Q / e ]

Charge of one electron

n (e) = 0.25 / 1.602 x 10^{-19}

n (e) = 0.25 x 10^{19} / 1.602 = 1.5605493 x 10^{18}

Thus, there are 1.56 (1.5605493) x 10^{18} electrons flowing in 0.5 A current in 2 s.

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