Question

a current of 0.6 A is drawn by a filament of an electric bulb for 5 minutes.find the amount of electric charge that flows through the circuit​

Answer 1

Answer:

5×60seconds = 300s

current = charge / time

0.6 = Q/ 300

Q = 300×0.6

Q = 180c

hence, the amount of electric charge that flows through the circuit is 180.

Answer 2

We get the amount of electric charge that flows through the circuit​ as 180 Coulomb.

Given,

Current = 0.6 A

Time for which current flows = 5 minutes

To Find,

The amount of electric charge that flows through the circuit​

Solution,

We know that,

Charge = Current x Time (in seconds)

Q = I x T

Where Q is the charge, I is the current and T is the time

Time is given to us in minutes, we need to first convert it into seconds

T = 5 minutes

1 minute = 60 seconds

T = 5 x 60 seconds

T = 300 seconds

I = 0.6 A

Q = 0.6 x 300

Q = 180 Coulomb

Hence, we get the amount of electric charge that flows through the circuit​ as 180 Coulomb.

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