a current of 0.8A drawn by a filament of electric bulb for 10 minutes find the amount of charge that flow through the circuit.
Answers
★ Given:-
- I = 0.8 A
- T = 10 min
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★ To find:-
- The amount of charge
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★ Formula Used:-
- Current ( I )= Amount of charge ( Q ) / time ( t )
- Amount of charge ( Q )= Current ( I ) × time ( t )
- Q = I × t
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★ Solution:-
converting Time:-
- ⇒ 1 min = 60 sec
- ⇒ t = 10 × 60
- ⇒ t = 600 sec
Therefore the time is 600 seconds.
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★ The amount of charge:-
- ⇒ I = Q/t
- ⇒ Q = I × t
- ⇒ Q = 0.8 × 600
- ⇒ Q = 480
Therefore the amount of charge is 480 coulomb
Given information to us:
- Amount of current = 0.8A
- Time period through which electric current had been flown by filament = 10 minutes
What's the need to be calculated:
- Amount of charge which had been flown through the circuit.
Performing calculations:
Here we had been given with the values of current and time. So let us understand the explaination first.
Let a current I be allowed to flow through a conductor of resistance R for time period t, whereas when a source of potential difference V is connected at its ending point.
Let a current I be allowed to flow through a conductor of resistance R for time period t, whereas when a source of potential difference V is connected at its ending point. We would be required to find the amount of electrical energy or amount of charge.
As due to flow of current I for time t, the amount of charge passed would be:
➟ Q = I × t
As the time is in hours so it can't be used directly firstly we would convert it into seconds.
➟ We know that 1 minutes contains 60 seconds
➟ 10 minutes would contain seconds = 10 × 60
➟ We came to knew 10 minutes contains 600 seconds.
Now substituting the values:
➟ Amount of charge (Q) = 0.8 × 600
Solving now,
➟ Amount of charge (Q) = 8/10 × 600
➟ Amount of charge (Q) = 8 × 60
➟ Amount of charge (Q) = 480
Conclusion:
- 480 coulomb