A current of/0.965 ampere is passed/thriugh 500ml of/0.2 m solution of/znso4 for/10/minutes
Answers
Answered by
124
The equation:
Zn²⁺ + 2e⁻ ----> Zn
1 mole is deposited by : 2 × 96500 C = 193000 C
The charge supplied = 0.965 × 10 × 60 = 579 C
how many moles are deposited by this charge :
579 / 193000 = 0.003 moles
Moles in 500 ml:
(500 / 1000) × 0.2 = 0.1 moles
Moles remaining in the 500 ml solution are :
0.1 - 0.003 = 0.097 moles
Molarity is :
(1000 / 500 ) × 0.097 = 0.194 M
Zn²⁺ + 2e⁻ ----> Zn
1 mole is deposited by : 2 × 96500 C = 193000 C
The charge supplied = 0.965 × 10 × 60 = 579 C
how many moles are deposited by this charge :
579 / 193000 = 0.003 moles
Moles in 500 ml:
(500 / 1000) × 0.2 = 0.1 moles
Moles remaining in the 500 ml solution are :
0.1 - 0.003 = 0.097 moles
Molarity is :
(1000 / 500 ) × 0.097 = 0.194 M
Answered by
13
Explanation:
Zn2+ +2e- gives Zn.
hope it helps u
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