Question

A current of (1.3+-0.2) dlows in a resistance when a potential difference of (50+-0.5) v is applied.calculate the value of resistance with the limits of error?

Answer 1

R=V/I

∆R=(I∆V-V∆I)/I^2

∆R=(1.3×0.5-50×0.2)/1.3^2

∆R=-9.35/1.69

∆R=+-15.8

R=V/I

R=50/1.3

R=38.46

hence value of resistance is 38.46+-15.80