Question

A current of 1.5 a flows through a conductor for 2.0 s. what amount of charge passes through the conductor?

Answer 1

Hey

We know,
--> Current is defined as the rate of flow of charge
=> I = Q / t ;

Now, 
--> 1.5 A = Q / 2s
=> Q = 3 As = 3C

Hence, three coulomb charge flows through the conductor in 2s..

Again,
--> Q = ne [ where e = charge of an electron = 1.6 * 10^(-19)C ]

Hence, n = Q/e = ( 3 / 1.6 ) * 10^19 = 1.88 * 10^19

So, finally, the amount of charge passing through the conductor at defined interval = 1.88 * 10^19 

Hope this helps ^_^