Question

A current of 1.5 A flows through a conductor for 2.0 s. What amount of charge passes through the conductor? Also calculate the number of electron passing through the cross section in 2.0 seconds​

Answer 1

Answer:

Charge Q =3coulumb. number of electrons=1.875×10^19

Explanation:

Current I=Q/t

So,

Q=It

=1.5×2

=3coulumb

Now, Quantization of Charge is given by,

Q=ne where n=number of electrons & e =charge of one electron

3=n×1.6×10^-19

n=3/1.6×10^-19

n=1.875×10^19

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Answer 2

Answer:

Data :

I = 1.5 A

T = 2.0 s

e = 1.6*10^-19

Using the formula :--

Q = I * T

Q = 1.5 A * 2. 0 s

= 3 C

Now, we find the number of electron

n = Q * e

= 3C * 1.6 * 10 ^-19

= 1.88 * 10 ^19

Hence, the number of electron is 1.88 * 10 ^19.