Question

a current of 1.5 ampere flows through a conductor for 10 seconds calculate number of electrons urgent

Answer 1

Given

• Current, I = 1.5 A
• time , t = 10 sec

To find

No. of electrons flowing through the conductor

Knowledge required

◆ Relation between I , Q and t where I is the current , Q is the charge through the conductor and t is the time for which current flows

$\red{\bigstar}\boxed{\sf{I=\frac{Q}{t}}}$

◆ No. of electrons having 1 Coulomb charge

$\boxed{\sf{6.25\times10^{18}\;\;electrons }}$

Solution

Finding the charge through the conductor having 1.5 A of current for time of  10 sec

$\blue{\implies}\sf{Q=I \times t}\\\\\blue{\implies}\sf{Q=1.5\times 10}\\\\\blue{\implies}\underline{\underline{\sf{Q=15\;\;C}}}$

Finding the no. of electrons through the conductor having 15 C of charge

$\blue{\implies}\sf{No.\;of\;electrons\;for\;1\;C\;charge=6.25\times 10^{18}}$

$\blue{\implies}\sf{no.\;of\;electrons\;for\;15\;C = 6.25\times10^{18}\times15}\\\\\blue{\implies}\underline{\boxed{\sf{No.\;of\;electrons\;in15\;C=93.75\times10^{18}}}}$

Answer 2

Answer:

$\huge \orange{ \overbrace{ \red{\underbrace \color{blue} {\underbrace \color{black}{\colorbox{lime}{ {\red \: {☘ Question☘ }}}}}}}}$

• A current of 1.5 ampere flows through a conductor for 10 seconds calculate number of electrons urgent.

$\fbox\color{red}\underline{Given:-}$

• Current, I = 1.5 A

• time , t = 10 sec

$\fbox\color{red}\underline{To find:-}$

• No. of electrons flowing through the conductor

$\fbox\color{red}\underline{Concept:-}$

◆ Relation between I , Q and t where

• I is the current ,

• Q is the charge through the conductor and

• t is the time for which current flows

$\red{\bigstar}\boxed{\sf{I=\frac{Q}{t}}}$★

• ◆ No. of electrons having 1 Coulomb charge

$\boxed{\sf{6.25\times10^{18}\;\;electrons }}$

$\fbox\color{red}\underline{Solution:-}$

• Finding the charge through the conductor having 1.5 A of current for time of 10 sec

$\begin{gathered}\green{\implies}\sf{Q=I \times t}\\\\\blue{\implies}\sf{Q=1.5\times 10}\\\\\blue{\implies}\underline{\underline{\sf{Q=15\;\;C}}}\end{gathered}$

• Finding the no. of electrons through the conductor having 15 C of charge

$\blue{\implies}\sf{No.\;of\;electrons\;for\;1\;C\;charge=6.25\times 10^{18}}$

$\begin{gathered}\blue{\implies}\sf{no.\;of\;electrons\;for\;15\;C = 6.25\times10^{18}\times15}\\\\\blue{\implies}\underline{\boxed{\sf{No.\;of\;electrons\;in15\;C=93.75\times10^{18}}}}\end{gathered}$