A current of 1.5A flows through a conductor for 4 seconds. What charge passes through the
conductor? How many electrons are transferred through the conductor?
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Answer:
3.75*10^19 electrons
Explanation:
I = Q/t
Q = I*t. here
I = 1.5 A and t = 4 sec.
Q = 1.5*4=6 C(coulomb)
One electon consists of a charge of 1.6*10^-19 C. Then the number of electrons passing would be:
Q=n*e
n=q/e
n=6/1.6*10^-19
n=3.75*10^19 electrons
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