Question

. A current of 1.6 mA flows through a conductor. If
charge on an electron is - 1.6 x 10-19 coulomb, find
the number of electrons that will pass each second
through the cross section of that conductor.​

Answer 1

Answer:

${10}^{16} \: electrons \: per \: second$

Explanation:

Given

i = 1.6 mA

$i \: = 1.6 \: \times {10}^{ - 3} ampere$

$e \: = \: 1.6 \times {10}^{ - 19}$

Q = ne = it

Then,

ne = it

$\frac{n}{t} = \frac{i}{e} \\ \frac{n}{t} = \frac{ {1.6 \times 10}^{ - 3} }{ {1.6 \times 10}^{ - 19} } \\ \frac{n}{t} = {10}^{ - 3 + 19} \\ \frac{n}{t} = {10}^{16} electrons \: per \: second$

Here, Q = charge

n = number of electrons

t = time

i = current

e = charge on one electron

$e \: = \: - 1.6 \times {10}^{ - 19}$

n/t represents number of electrons per second.