A current of 1 A is drawn by a filament of a electric bulb . Number of electron passing through a cross section
of a filament in 16 second
would be roughly
a.) 10 ^ 20
b.) 10^16
c.) 10^18
d.) 10^23
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Answers
Answered by
2
Answer:
b 10^16
Explanation:
vaise current is charge per unit time...
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Answered by
4
Answer:
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option a : 10^ 20 electrons
l = Q/ t
Q= It
Q = 1× 16
Q = 16 q
Q= ne
n= Q/ e
n= Q/ e
n= 16/ 1.6× 10 ^ -19
n = 10 × 10 ^ 19
n= 10^ 20 electrons
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