Question

a current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 48 seconds would be

Answer 1

3×10^20 electron passed in fourty eight second

Answer 2

Hiii
Ur answer is 
Current given= 1A
Time=48sec
As I=Q/T or I=ne/T
Then N= I*T/e
1*48/1.6*10^-19
= 30*10^19 electrons
Hope u understand 
Please mark my brainlist plzz
Thank You