Question

A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in 16 seconds would be roughly(explain the answer)

Answer 1

Answer:

since we know , I = Ne/T where N is the number of electrons passing through the cross sectional area of a conductor and e is the charge of 1 electron , T stands for the time duration of flow of current.

accordingly , 1 = N x 1.6*10^-19c / 16s

thus N = 10^20 electrons.

number of electrons passing through a cross section of the filament in 16 seconds is 10^20.

hope this helps.