Question

a current of 1 ampere flow in a series circuit contain an electric lamp and a conductor of 5 ohm when connected to a 10 watt battery. calculate the resistance
​

Answer 1

➠ AnSwer :-

➝ Case 1 :

➝ given :-

• V = 10

Total Resistance in the series = 5+R

we know that

→ I = V/R

→ I = 10/(5+R)

➝ Case 2:

As the resistance are in parallel series so,

Total Resistance = (R¹ × R² )/( R¹+R²)

→ I = V/R

→ I = 10/5

→ I = 2 Amp

current in each branch = 2/2 = 1

(both of the branches have same resistance and because of it the current is divided equally.)

Potential across the lamp+ Conductor = 10V

Potential across the lamp = 5 V