Question

A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 ohms when connected to a 10V battery . Calculate the resistance of the electric lamp, now if a resistance of 10 ohms is connected in parallel with this series combination , what change (if any) in current flowing through 5ohms conductor and potential difference across the lamp will take place ? Give reason​

Answer 1

Explanation:

I= 1A

R=5ohm

V=10v

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Answer 2

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(i) Total Resistance

$I=1A$

$V=10V$

$\mapsto$$R=\frac {V}{I}$

$\mapsto$$R=\frac{10V}{1A}$

$\implies$R=10ohm

Since, conductor of 5ohm

$\leadsto$ In Series;

$\mapsto$$R=5ohm+{R}{lamp}, {R}{lamp}$

$\mapsto$$R-5ohm=10$

$\mapsto$$I({R}{lamp}=(1A)(5ohm)$

$\implies$$=5V$

(ii) When,

$\mapsto$$R=10ohm$

$\leadsto$ In Parallel;

$\mapsto$$\frac {1}{R'}=\frac{1}{10}+\frac{1}{R}$

$\mapsto$$\frac {1}{R'}=\frac{1}{10}+\frac{1}{10}$

$\mapsto$$\frac {1}{R'}=\frac {1}{5}$

$\implies$$R'=5ohm$