a current of 1 ampere is drawn by a filament of an electric bulb what is the number of electron passing through a cross section of the filament in 16 second
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I=q/t
1=q/16
q=16Coulombs
Charge of an electron is 1.602×10^-19
No of electrons=10/1.602×10^-19
No of electrons=9.92×10^19
1=q/16
q=16Coulombs
Charge of an electron is 1.602×10^-19
No of electrons=10/1.602×10^-19
No of electrons=9.92×10^19
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