Question

A current of 1 ampere is drawn by a filament of electric bulb find the number of electrons passing through a cross section of the filament in 16 seconds

Answer 1

Since
I=Q/T
1=Q/16
Q=16c
No.of electrons=Q/charge of an electron
No. of electron=16×10^19/1.6

Answer 2

Answer:

given:

Current= 1A

Time = 16 s

Q=ne

It = ne (Q=It)

It/e =n (e=1.6 * 10^-19)

1*16/1.6 * 10^-19 =n

10*16/16 * 10^-19=n

10*10^-19=n

n = 10^20 e