A current of 1 ampere is drawn by a filament of electric bulb find the number of electrons passing through a cross section of the filament in 16 seconds
Answers
Answered by
18
Since
I=Q/T
1=Q/16
Q=16c
No.of electrons=Q/charge of an electron
No. of electron=16×10^19/1.6
I=Q/T
1=Q/16
Q=16c
No.of electrons=Q/charge of an electron
No. of electron=16×10^19/1.6
Answered by
13
Answer:
given:
Current= 1A
Time = 16 s
Q=ne
It = ne (Q=It)
It/e =n (e=1.6 * 10^-19)
1*16/1.6 * 10^-19 =n
10*16/16 * 10^-19=n
10*10^-19=n
n = 10^20 e
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