Question

A current of 1 ampere is flowing through a circular loop of 100 mm radius find the magnetic field at a point which is at a distance of 100 m from the centre of the slope on its Axis due to this current location calculate the magnetic field at the centre of this loop?

Answer 1

Answer: The magnetic field at point is $B = 6.28\times10^{-15}\ T$ and the magnetic field at the center of this loop is $B = 1\times10^{-6}\ T$.

Explanation:

Given that,

Current = 1 A

Radius r = 100 mm

Distance x = 100 m

We know that,

The magnetic field at point which is at a distance from the center is

$B = \dfrac{\mu_{0}Ir^{2}}{2(r^{2}+x^{2})^{\dfrac{3}{2}}}$

$B=\dfrac{4\pi\times10^{-7}\times1\times100\times 100\times10^{-6}}{2\times ((100\times10^{-3})^{2}+(100)^{2})^{\dfrac{3}{2}}}$

$B = 6.28\times10^{-15}\ T$

Now, the magnetic field at the center of this loop

$B = \dfrac{\mu_{0}I}{4\pi r}$

$B = \dfrac{4\pi\times10^{-7}\times1}{4\pi\times100\times10^{-3}}$

$B = 1\times10^{-6}\ T$

Hence, The magnetic field at point is $B = 6.28\times10^{-15}\ T$ and the magnetic field at the center of this loop is $B = 1\times10^{-6}\ T$.

Answer 2

in this question answer is solve the all steps