Question

A current of 1 ampere passes through a resistance of 100 Ohm in 418 seconds,the heat produced will be?
In J cal

Answer 1

Question :-

A current of 1 ampere passes through a resistance of 100 Ohm in 418 seconds,the heat produced will be?

Answer :-

Given :

Current ( I ) = 1 A

Resistance ( R ) = 100 Ω

Time ( t ) = 418 s

Heat produced = H = I² R t

                                =  ( 1 A )² × 100 Ω × 418 s

                                = 100 A Ω × 418 s

                                = 41800 J

We know that 1 cal =  4.18 J

4.18 J = 1 cal

Hence 41800 J = 10,000 cal

ANSWER :

The power produced is 41800 J or 10000 cal

Hope it helps !

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