Question

A current of 1 amphere is drawn by a filament of an bulb. Number of electrons passing through a cross section of the filament in 16 second is

Answer 1

9.9875× 10^(19)

Explanation:

I=Q/t

Given 1 A of current flows in 16 seconds.

Hence, charge Q=I×t= 16 Columbs.

Also we have, Q=ne

n= Q/e

16/1.602×10^(-19)

=9.9× 10^(19)