A current of 1 mA is flowing through a copper wire .How many electrons will pass a given point in one second
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q=It
q=ne (n=number of electrons ,,e =charge)
ne=It
n=It/e
n=10^_3×1/1.6×10^_19
n=0.625×10^_16 electrons
______hope it helps_____
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q=ne (n=number of electrons ,,e =charge)
ne=It
n=It/e
n=10^_3×1/1.6×10^_19
n=0.625×10^_16 electrons
______hope it helps_____
☺☺☺☺☺☺☺☺☺☺
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Here as per the question we have to use formula
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