Question

A current of 10 A flows in each of two conducting wires parallel to each other.The separation between the wires is 2 cm. Find the force per unit length of one of the wires.​

Answer 1

Answer:

Force on one wire due to other is F=BI

2

l where magnetic field B=

2πr

μ

0

I

1

due to first wire at distance r.

Thus force per unit length between them is F/l=BI

2

=

2πr

μ

0

I

1

I

2

=

2π×1

(4π×10

−7

)×10×10

=2×10

−5

N/m