Question

a current of 10 A is maintained in a conductor of cross-section 1 cm.if the number density of free electrons be 9×10,the drift velocity of free electrons is

Answer 1

The drift velocity of the electron is 6.94 x 10^17 cm/s.

• In the question, it is given that the current (I) = 10 A, desnisty of free electrons (n) = 9 x 10, and the area of cross-section of the wire (A) = 1 cm.
• We know, the expression for drift velocity is given by Vd = I/(n*e*A)

where, e = charge of an electron = 1.6 x 10^-19.

• Thus, Vd = 10/(9*10 * 1.6 x 10^-19 * 1) = 6.94 x 10^17 cm/s.