A current of 10 amp. is passed through molten AlCl3 for 96.5 seconds. Calculate the mass
of Al deposited.
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Answer:
Correct option is
A
10
Given m=0.9g
Oxidation number =3
5=96.5 s
i=X=?
m=
F
E
it
0.09=
3×96500
(27)×(965)
X=
27
0.9×3×1000
=10A
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