Question

a current of 10 ampere flows in a wire for 10 sec. If a potential difference across the wire is 15 volt.the work done will be

Answer 1

given: current=10A

           time=10 sec

           potential difference=15Volt

to find: workdone

solution: we know the formula to find W

              W=VQ

               so here we have only  V so first of all we must find Q

          so we use the formula I=Q/T

            therefore Q=IT (putting values in the formula)

                              Q=10 mutiple 10

                              Q = 100C

now put Q=100C in formula W=VQ

                                               W=15 mutiple 100

                                                w=1500J

hope it will help you.....................................

             

Answer 2

Concept:

When charges move in an electric circuit, they take with them some electrical energy. Work is done in the circuit when they travel from an area of higher to lower or lower to higher potential difference. The amount of energy transferred and the duration that charges were in motion can be used to calculate the rate of accomplishing work.

Find:

The work done by the supply.

Solution:

Work done = Potential difference × Current× time

$work=15 \times 10 \times 10\\work=1500J$

Hence, the work done is $1500J$.

#SPJ2