A current of 10A exists in a conductor Assuming that this current is entirely due to the
now of electrons (a) find the number of electrons crossing the area of cross section per
second, (b) if such a current is maintained for one hour find the net flow of charge
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Answer:
I = 10 A
t =1 h = 60 x 60 = 3600 s
I = Q/t
Thus,
Q = I x t
Q = 10 x 3600 = 36000 C
Thus, no. of electrons crossing area of cross section per second is
Q = ne
n = Q/e = 36000/(1.6 x 10-19) = 22.5 x 1022
Explanation:
Hope it helps
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