Physics, asked by bothraharahita, 10 months ago

A current of 10A flows through a conductor for 2 minutes

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Answers

Answered by Anonymous

6

Answer:

I=10A

t=2s

a)I=q/t

10=q/2×60

q=1200C

b)q=n e

1200=n × 1.6×10^-19

n=1200/1.6×10^-19

n=7.5×10^21

Answered by Kartikposwal

1

Answer:

l=10A

T=2minutes=120seconds

I=Q/T

10=Q/120

Q=1200C

Now

e=1.6*10^-19

By Quantization of charge

Q=ne

1200=n*1.6*10^-19

n=1200/1.6*10^-19

n= 750/10^-19

n=750*10^19

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