Question

A current of 10A flows through a resistor for 10 minutes
and the power dissipated by the resistor is 100 W. Find
the P.D. across the resistor and the energy supplied to
the circuit.


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Answer 1

Explanation:

ANSWER:-

Given:-

• A current of 10 Amperes
• Time through which it is flowing is 10 minutes
• Power dissipated is 100 W

To find:-

• We need to find the potential difference
• We need to find the energy.

Let's Go!

Whenever I attempt a question I check whether there are inquisitive unit games. We need to use SI Unit only. Can you see which glitch I am talking of? The time should be in seconds and not in minute.

So, sing-song starts as we know 1 minute = 60 seconds.

So, 10 minutes will have 600 seconds.

Now, we need to note:-

$\rm{Voltage = Current \times Resistance}$

We need not use thi formula as data given not applicable, so next is -

$\rm{Power = Voltage \times Current}$

$\rm{100 = Voltage \times 10}$

$\rm{\dfrac{100}{10} = Voltage }$

$\rm{Voltage= 10 \ V}$

Done? Let's move forward.

We need the next value as energy. So, we need to note:-

$\sf{Energy = Voltage \times Current \times Time}$

$\sf{Energy = 10 \times 10 \times 600}$

$\sf{Energy = 6 \times 10^{4} \ Joules }$

So, these were the required answers.

Answer 2

Answer:

Given :-

• Current = 10 A
• Time = 10 min
• Power dissipated = 100 W

To Find :-

• Potential Difference
• Energy

Solution :-

1 min = 60 sec

10 min = 10 × 60 = 600 sec

$\huge \frak \red{P = VQ}$

P is the Power

V is the Voltage

C is the Current

⟹ 100 = V × 10

⟹ 100 = 10V

⟹ V = 100/10

$\frak \pink{V\: = 10V}$

Now

Finding Energy

$\huge \frak \red{E = VQT}$

E = Energy

V = Voltage

Q = Charge

T = Time

⟹ E = (10)(10)(600)

⟹ E = 100 × 600

⟹ E = 6 × 10⁴ Joules