Question

A current of 10A is pass for 80min and 27sec. through a cell containing Dil.h2so4.How many moles of oxygen will be Liberated as anode.

Answer 1

In the picture, 4 g of oxygen is liberated.

32 g of O2 is present in 1 mol of O2

∴4 g of O2 is present in 1/32 x 4=0.125 mol of O2

Therefore, 0.125 moles of O2 is released at the anode.

Thank u..

Answer 2

Answer:

4 g of Oxygen gas is liberated

Explanation:

Current, I = 10 A

Time, t = 80 min and 27 second

= (80 X 60) + 27 = 4827 seconds

Given:

Charge, Q = It

Q = 10X 4827

= 48270 F

Now in electrolysis of H2SO4, H2 and O2 liberated as follows:

At cathode:

2H+ 2e→ H2

At anode:

2H2O→O2+4H+ 4e

4F liberate 1 mole of Oxygen gas or 32 g of Oxygen.

32 g of Oxygen.4F or 4X 96500 C will liberate 32 g of Oxygen gas

48270 C will liberate 48270 x32 /4x96500

= 4 g of Oxygen gas

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