A current of 12 mA flows through a circuit when 2V battery is turned on. The power dissipated in the circuit is ___W.
a) 24
b) 0.024
c) 0.6
d) 1600
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Answer:
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Answered by
1
Answer:
P=IV
P=12×10^(-3) × 2
P=24×10^(-3)
P=0.024
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