Physics, asked by Nimo07, 5 hours ago

A current of 12 mA flows through a circuit when 2V battery is turned on. The power dissipated in the circuit is ___W.
a) 24
b) 0.024
c) 0.6
d) 1600​

Answers

Answered by krishg9452663452
0

Answer:

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Answered by cipapi9588
1

Answer:

P=IV

P=12×10^(-3) × 2

P=24×10^(-3)

P=0.024

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