Question

A current of 12 mA flows through a circuit when 2V battery is turned on. The power dissipated in the circuit is ___W.
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Answer 1

★ Question :-

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⟶ A current of 12 mA flows through a circuit when 2V battery is turned on. The power dissipated in the circuit is ________ W.

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★ Answer :-

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⟶ The Power is 0.024 Watt .

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★ Explanation :-

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⟶ Given =

• Current [ I ] = 12 mA
• Voltage [ V ] = 2 V
• Power [ P ] = ?

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⠀⠀⠀$\maltese \: \large \bold \red{As \: we \: know,} \\ \\ \boxed{\bold{P = V \times l}} \\ \\ \\ \bold \pink{Now, \: Let's \: \: Substitute :- } \\ \\ \rightarrow\bold {P = 2 \times ( \: 12 \times 10 {}^{ - 3)} } \\ \\ \rightarrow \bold{P = 24 \times (10 {}^{ - 3}) } \\ \\ \rightarrow \bold{P = 24 \times 10 {}^{ - 3} } \\ \\ \mapsto\boxed{ \bold \red{P = 0.024 \: watt}}$

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★ Hence,

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• The Power is = $\bold\pink{0.024\:watt}$

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★ $\underline{\large\mathcal\red{Formula\: Required\::-}}$

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⠀⠀⠀⠀$\boxed{\footnotesize\bold{Power = Voltage × Current }}$

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$\large\colorbox{pink}{Hope lt'z Help You ❥ }$