A current of 120 milli ampere flows through the circuit for 4 minutefind the amount of charge and no. of electrons.
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Answer:
Q=28.8 C
n=18*10^19
Explanation:
Q= it= (120*10^-3)*(4*60)
=28.8 C
Q=ne
=> n = q/e =28.8/(1.6*10^-19)
=18 * 10^19
hope it helps.....pls mark me as brainliest....
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