Question

a current of 16 A is flowing through a circuit for 0.5 seconds, the number of electrons flowing is :

Answer 1

y

Charge flow Q=i×t=0.5×2=1

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n=

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n= 1.6×10

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n= 1.6×10 −19

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n= 1.6×10 −19

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n= 1.6×10 −19 1

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n= 1.6×10 −19 1

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n= 1.6×10 −19 1 = 6.25×10

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n= 1.6×10 −19 1 = 6.25×10 18

Charge flow Q=i×t=0.5×2=1we know that Q=ne where n is no. of electrons.So, number of electrons n= 1.6×10 −19 1 = 6.25×10 18 electrons.

Answer 2

Given,

Current (I)= 16A

Time (t) = 0.5 secs

To Find,

The number of electrons (ne) flowing through the circuit.

Solution,

As we know,

⇒Q = I × t

Where Q is the quantity of charge flowing by a point in a time period (t).
⇒Q = 16 × 0.5

⇒Q = 8C

Now,

⇒Q = ne

Substituting value of electrons which is 1.6 × 10^-19 in (e)

⇒ 8 = n × 1.6 × 10^-19

⇒ n = 8 /  1.6 × 10^-19

⇒ n = 80 × 10^-19 / 16

⇒ n = 5 × 10^-19

Hence, the number of electrons flowing through the circuit is 5 × 10^-19.