A current of 1A drawn by a filament of an electric bulb. Number of electron passing through a cross-section of the filament in 16 second would be roughly
Answers
Explanation:
The relationship between current, charge and time is given as follows.
charge = current x time, that is, Q = It where,
charge is Q, it is measured in coulombs (C)
current is I, it is measured in amperes (A)
time is t, it is measured in seconds (s).
The relationship between electronic charge, charge and number of electrons are protons is given as follows.
charge = number of electrons or protons x electronic charge, that is Q = ne
where,
charge is Q, it is measured in coulombs (C)
number of electrons/protons is n, it is measured in numbers
electronic charge is e, it has a standard value = 1.6×10
−19
Coloumbs (C).
Equating both the above equations, that is,
It = ne we get,n= eI×T= 1.6×10 −191×16 =1020
.
Hence, number of electrons passing through a cross section of the filament in 16 seconds would be roughly 1020
.
Answer:
The number of electrons passing through a cross section of the filament in 16 seconds is 1 \bold{\times 10^{20}}×10
20
Explanation:
The electrons passing through the cross section of an electric bulb’s filament have drawn current of 1 A will be calculated through knowing the charge.
As we know that, charge is the current flowing in time and also the number of electron possessed is charge. So, from here, we have –
Q=I \bold{\times}× t as well as Q = n e; where Q is the charge, I is the current, t is the time and n is the number of electron e.
\begin{gathered}\begin{aligned} Q=& I \times t \text { and } Q=n \times e \\ & I \times t=n \times e \\ 1 \times 16=& n \times e \\ \frac{16}{e}=& n \\ n=& \frac{16}{1.6 \times 10^{-19}} \end{aligned}\end{gathered}
Q=
1×16=
e
16
=
n=
I×t and Q=n×e
I×t=n×e
n×e
n
1.6×10
−19
16
n=1 \times 10^{20}×10
20
number of electrons flows through the filament in 16 seconds.