A current of 1A flows through a wire of length 0.24m &area of cross section 1.2mm2.,when it is connected to a battery of 3V. Find the no. Density of free electron in the wire, if the electron mobility is 4.8x10*-6
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Explanation:
Three resistors each of 3Ω
A battery of 10 Volt
To Find:
Current across one of the 3 ohm resistors
Solution:
We know that,
In series combination
Current through each resistance is same as that of main current flowing through the circuit i.e. I=I₁=I₂=I₃=.......
Equivalent resistance is equal to the sum of individual resistances
i.e.
For a circuit,
where
I is current flowing through circuit
V is potential across battery
R is resistance of circuit
Now,
Let the equivalent resistance of given circuit be R
So,
Now,
Let the current flowing through the circuit be I
So,
Therefore, current flowing through across each of the 3Ω resistor is 10/9 A.
Hence, the required current is 10/9 A.
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