Question

A current of 1A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly

Answer 1

I = Q/t
Q = It
Also It = number of electrons × charge of electron
It = NE
Where N is the number of electrons
1 × 16/ 1.6 × 10^-19 it comes to 10^ 20

Answer 2

Answer:

The number of electrons passing through a cross section of the filament in 16 seconds is 1 $\bold{\times 10^{20}}$

Explanation:

The electrons passing through the cross section of an electric bulb’s filament have drawn current of 1 A will be calculated through knowing the charge.

 

As we know that, charge is the current flowing in time and also the number of electron possessed is charge. So, from here, we have –

 

Q=I $\bold{\times}$ t as well as Q = n e; where Q is the charge, I is the current, t is the time and n is the number of electron e.  

$\begin{aligned} Q=& I \times t \text { and } Q=n \times e \\ & I \times t=n \times e \\ 1 \times 16=& n \times e \\ \frac{16}{e}=& n \\ n=& \frac{16}{1.6 \times 10^{-19}} \end{aligned}$

n=1 $\times 10^{20}$ number of electrons flows through the filament in 16 seconds.