A current of 1A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 48 seconds would be
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1020 electrons passing through a cross section of the filament in 48 seconds would be
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I= q/t
1= ne/40 as ., q = ne
40/e =n
40/1.6×10^-19 =n
3×10^20 =n
1= ne/40 as ., q = ne
40/e =n
40/1.6×10^-19 =n
3×10^20 =n
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