Question

A current of 1A is drawn by a filament of an electric bulb. Number of electrons

passing through a cross section of the filament in 16 seconds would be roughly

(a) 1020 (b) 1016 (c) 1018 (d) 1023

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Answer 1

Answer:

Hence, number of electrons passing through a cross section of the filament in 16 seconds would be roughly 1020.

Answer 2

Answer :

10^20

Explaination :

I = q/t = ne/t

n = I × t / e

since e = 1.6 × 10^-19c

So, n = 1A × 16 sec/ 1.6 × 10^-19 c

n = 16 × 10^19 / 1.6

n = 10^20 e