A current of 1A is drawn by a filament of an electric bulb. Number of electrons
passing through a cross section of the filament in 16 seconds would be roughly
(a) 1020 (b) 1016 (c) 1018 (d) 1023
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1
Answer:
Hence, number of electrons passing through a cross section of the filament in 16 seconds would be roughly 1020.
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4
Answer :
10^20
Explaination :
I = q/t = ne/t
n = I × t / e
since e = 1.6 × 10^-19c
So, n = 1A × 16 sec/ 1.6 × 10^-19 c
n = 16 × 10^19 / 1.6
n = 10^20 e
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