A current of 1ampere is drawn by a filament of an electric bulb find the number of electrons passing through a cross sections of the filament in 16sec?
Answers
Answered by
8
hey mate !
I = q/ t
q = I t
q= 1 * 16
q = 16C
now ,
apply formula. .
q =ne
n = No. of electrons
e= charge of electron
n = q/e
n = 16/ 1 .6 *10^-19
n = 10^20 electrons..
#Phoenix
I = q/ t
q = I t
q= 1 * 16
q = 16C
now ,
apply formula. .
q =ne
n = No. of electrons
e= charge of electron
n = q/e
n = 16/ 1 .6 *10^-19
n = 10^20 electrons..
#Phoenix
Answered by
0
The number of electrons passing through a cross section of the filament in 16 seconds is 1
Explanation:
The electrons passing through the cross section of an electric bulb’s filament have drawn current of 1 A will be calculated through knowing the charge.
As we know that, charge is the current flowing in time and also the number of electron possessed is charge. So, from here, we have –
Q=I t as well as Q = n e; where Q is the charge, I is the current, t is the time and n is the number of electron e.
n=1 number of electrons flows through the filament in 16 seconds.
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