Question

A current of 2.1A flowing in a wire. How many electrons pass a given point in the wire in 1 second

Answer 1

Explanation:

refer above attachment for answer

Answer 2

we have formula,

I=Q/t

I=current

Q=charge

t=time

charge = number of electrons or protons*charge of electron

Q=n*e

Q=It

Q=2.1*1=2.1

n*e=2.1

charge of electron=1.6*10^-19 columbs

n=2.1/(1.6*10^-19)

n=1.3125*10^19 protons pass a given point in 1 second

hope this helps ;)