A current of 2.5 ampere is drawn by a filament of an electric bulb for 2 minutes find out the amount of charge close to the circuit
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t=2min=2*60sec,t=120sec
I= 2.5A
Q=?
I=Q/T
2.5=Q/120
Q=2.5*120
Q=300colomb.
I= 2.5A
Q=?
I=Q/T
2.5=Q/120
Q=2.5*120
Q=300colomb.
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