A current of 2 A flowing through a 2 ohm resistor when connected across a battery. The same battery supplies a current of 0.5 A when connected across a 9 ohm resistor. what is the internal resistance of the battery?
Answers
Answered by
167
~♥~Hey Deepjaya~♥~
→_→→_→→_→→_→→_→
your answer is "1/3 ohm"
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Explaination ☞
→_→→_→→_→
we know that
current ,
=> I = E/{R+r}
=> 2= E/{2+r} ______eq(1)
again
=> 0.5 = E/{9+r} ______eq(2)
from eq(1) and eq(2)
we get,
=> 2/(0.5) = (9+r)/(2+r)
=> 4 = (9+r)/(2+r)
=> 8 + 4r = 9 + r
=> 3r = 1
=> r = 1/3 ohm ______answer
I think my answer is capable to clear your confusion
Devil_king ▄︻̷̿┻̿═━一
→_→→_→→_→→_→→_→
your answer is "1/3 ohm"
→_→→_→→_→→_→→_→
Explaination ☞
→_→→_→→_→
we know that
current ,
=> I = E/{R+r}
=> 2= E/{2+r} ______eq(1)
again
=> 0.5 = E/{9+r} ______eq(2)
from eq(1) and eq(2)
we get,
=> 2/(0.5) = (9+r)/(2+r)
=> 4 = (9+r)/(2+r)
=> 8 + 4r = 9 + r
=> 3r = 1
=> r = 1/3 ohm ______answer
I think my answer is capable to clear your confusion
Devil_king ▄︻̷̿┻̿═━一
Answered by
12
Answer: 1/3
Explanation: use the formula of internal resistance you will get 2 equations equate them
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