A current of 2 A is carried by a uniform wire of 50 m long. If the fall in potential along the wire is 12V ,it's resistance per metre would be
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from ohm's law V=ir
given that i=2A V=12V then r(resistance)=V/i = 12/2=6
Now resistance = rho×L/A
6= rho×50/A
6/50= rho/A
0.12=rho/A(since resistivity and area are constant)
given that i=2A V=12V then r(resistance)=V/i = 12/2=6
Now resistance = rho×L/A
6= rho×50/A
6/50= rho/A
0.12=rho/A(since resistivity and area are constant)
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