a current of 2 a is flowing through 10 om resistor for 20 min
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I - 2a
R - 10ohm
t - 20 mim - 20×60 = 1200
J = R × I² × t
J = 10 × 2^2 × 1200
J = 10 × 4 × 1200
J = 40 × 1200
J = 48000
48000J = 48Kj
the answer is 48Kj
R - 10ohm
t - 20 mim - 20×60 = 1200
J = R × I² × t
J = 10 × 2^2 × 1200
J = 10 × 4 × 1200
J = 40 × 1200
J = 48000
48000J = 48Kj
the answer is 48Kj
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0
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