Question

a current of 2 a is flowing through 10 om resistor for 20 min

Answer 1

I - 2a
R - 10ohm
t - 20 mim - 20×60 = 1200

J = R × I² × t
J = 10 × 2^2 × 1200
J = 10 × 4 × 1200
J = 40 × 1200
J = 48000

48000J = 48Kj

the answer is 48Kj

Answer 2

u have not mentioned what to find...