Question

a current of 2 amp is drawn by a filament by an electric bulb. no of electrons passing through a cross section of the filament in 8 seconds would approximately​

Answer 1

Required Answer:-

GiveN:

• Current passing = 2 A
• Time taken = 8 seconds.

To FinD:

• No. of electrons passing through a cross section of the filament?

Step-wise-step Explanation:

We know that,

$\large\boxed{ \rm{I = \dfrac{Q}{t} = \dfrac{ne}{t} }}$

Then, ne = I × t

Now putting the given values along with the charge of electron in place of e i.e. 1.6 × 10-¹⁹ C.

⇒ n × 1.6 × 10-¹⁹ = 2 × 8

⇒ n = 16 / 1.6 × 10-¹⁹ electrons

⇒ n = 10²⁰ electrons

Hence:-

• The no. of electrons that will pass through the current carrying filament is 10²⁰ electrons.

Answer 2

$\huge{\boxed{\rm{Question}}}$

A current of 2 amp is drawn by a filament by an electric bulb. no of electrons passing through a cross section of the filament in 8 seconds would approximately.

$\huge{\boxed{\rm{Answer}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• Passing current through filament = 2 Ampere's.

• Taken time = 8 seconds.

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• Number of electrons passing through a cross section of the filament ( approx ).

$\large{\boxed{\boxed{\sf{Solution}}}}$

• Number of electrons passing through a cross section of the filament = 10²⁰

$\large{\boxed{\boxed{\sf{What \: does \: the \: question \: says}}}}$

$\large{\boxed{\boxed{\sf{Let's \: understand \: the \: concept \: 1st}}}}$

• This question says that a current of 2 Ampere's is drawn by a filament by an electric bulb afterthat it says that no. of electrons passing through a cross section of the filament in 8 seconds would approximately. In short it says that that the current takes time of 8 seconds. And now the question ask us to find the number of electrons passing through a cross section of the filament.

$\large{\boxed{\boxed{\sf{How \: to \: solve \: this \: question}}}}$

$\large{\boxed{\boxed{\sf{Let's \: see \: the \: procedure \: now}}}}$

• To solve this question firstly we have to use a formula and the formula is ɪ = Q/t = ne/t. Afterwards we also know that ne = l × t. Now putting the values along with the charge of electron in the place of "e". i.e., 1.6 × 10-¹⁹ C. After putting the values we get our final result that is 10²⁰. Means number of electrons passing through a cross section of the filament = 10²⁰. Hence, we have done !

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

Using formula ↝

• ɪ = Q/t = ne/t

Putting the values according to this formula we get the following results ↝

• n × 1.6 × 10-¹⁹ = 2 × 8

• n = 16 / 1.6 × 10-¹⁹ ( 2 × 8 = 16 )

• n = 10²⁰.

Hence, number of electrons passing through a cross section of the filament = 10²⁰ electrons.