Question

a current of 2 ampere exists in a wire of cross section area 1 mm square if its cubic metre of the wire contains 6 ×10 power 28 free electrons find the drift speed ​

Answer 1

Given :

Current in the wire = 2 A

Cross sectional area of the wire = 10 ^ (-6) m^2

Number of free electrons = 6 * 10^28

To find :

The drift speed .

Solution :

Drift speed , v$_d$ = ( current ) / ( number of free electrons * charge of electron * area of cross section of wire )

Now , using the values given in question ,

Drift speed , v$_d$ = 2 / [ 6 * 10^28 * 1.6 * 10^(-19) * 10^(-6) ]

=> v$_d$ = 2 / ( 9.6 * 10^3 )

=> v$_d$ = 2.08 * 10^(-4) m/s

The value of the drift speed is 2.08 * 10^(-4) m/s  .

Answer 2

Explanation:

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