Math, asked by anshu674, 1 year ago

a current of 2 ampere produced 200 joule of heat in a wire in a given period of time if the current is increased to 4 ampere how much heat will be produced in same time

Answers

Answered by saush70
7
Hey dear,

Heat =I²R
So,200 joule of heat=(2)²*R
R=200/4=>50 ohm
So,for 4 ampere
Heat =(4)²*50
=>16*50
=>800 joule
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saush70: please mark as BRAINLIEST
anshu674: but heat = i²Rt
saush70: but the answer comes correct
anshu674: Answer does not mean the answer can come either
saush70: please mark as BRAINLIEST
saush70: tank you so much
Answered by shivanidixit2002
5

Answer:

800 joule

Step-by-step explanation:

please mark this answer the brainliest..

we know that H=I²RT

case 1

200=2²*RT

RT=200/4=50

case 2

H=4²RT

since resistance and temperature and time remain same for the second case

we substitute the value of RT from case 1

H=4²*50=16*50=800  joule

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Hope it helps!!




anshu674: T for time not temperature
anshu674: ok are you understand
shivanidixit2002: i know
shivanidixit2002: it is already given in the question
shivanidixit2002: btw it should be do you understand
shivanidixit2002: please mark me the brainliest3
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